\begin{alignat}{3}
G(6)\,H(1) - G(1)\,H(6) &= 
\frac{\eta(\tau)\eta(6\tau)}{\eta(2\tau)\eta(3\tau)},&\quad &\Gamma_1(30), &\quad -B=8,
\mylabel{eq:RR511}\\
G(11)\,H(1) - G(1)\,H(11) &= 
1
,&\quad &\Gamma_1(55), &\quad -B=40.
\mylabel{eq:RR512}
\end{alignat}